So you tell Arbegla, well, if you really want us to figure this out, you need to give us more information. You pick any x and then the corresponding y for each of these could be a solution for either of these things. These are all of the prices for bananas and apples that meet this constraint.
So in any situation for any per pound prices of apples and bananas, if you buy exactly three times the number of apples, three times the number bananas, and have three times the cost, that could be true for any prices.
And three pounds of bananas is going to cost 3b, three pounds times b dollars per pound. You have to multiply the entire equation times negative 3 if you want the equation to still hold. And it is consistent, 0 equals 0. So go down by two, go down by 2.
We are left with b is equal to negative 2a plus 5. And if we were to graph that, our b-intercept when a is equal to 0, b is equal to 5. This is what we call, this is a consistent system. He says, my fault.
Six pounds of apples is going to cost 6a, six pounds times a dollars per pound. Our b-intercept is 5 and our slope is negative 2a. This system of equations is dependent. Now surely considering how smart you and this bird seem to be, you surely could figure out what is the per pound cost of apples and what is the per pound cost of bananas.
Let we mark off some markers here-- one, two, three, four, five and one, two, three, four, five. I have 6a here. So let me write this down. So this first white equation looks like this if we graph the solution set. But you start to wonder, why is this happening?
And it might be able to cancel out with all of this business. And you have an infinite number of solutions. This looks very similar, or it looks exactly the same. There was a slight, I guess, typing error or writing error.
All I did is subtract 2a from both sides. And then a few seconds later he storms back in. And on the right hand side, 15 minus 15, that is also equal to 0. So this is essentially the same line.
Every time you add 1 to a-- so if a goes from 0 to b is going to go down by 2. So you think for a little bit, is there now going to be a solution? And then 5 times negative 3 is negative Systems of linear equations and their solution, explained with pictures, examples and a cool interactive applet.
Also, a look at the using substitution, graphing and elimination methods.
Example of a system that has infinite solutions: Line 1:. InfinitelyManySolutions Linearsystemssometimeshaveinfinitelymanydifferentsolutions. Forexample,a 2 3 systemsuchas a Figure1:This2 3 systemhasinfinitely. Aug 09, · One solution, no solution, or infinitely many solutions. Skip navigation Sign in.
Search. System of Equations: One Solution, No Solution, or Infinitely Many Solutions One solution, no. A system of linear equations either has no solutions, a unique solution, or an infinite number of solutions. If it has solutions it is said to be consistent, otherwise it is inconsistent.
A system of linear equations in which there are fewer equations than unknowns is said to be underdetermined. How to Solve a System of Equations by Substitution Solving Equations with Infinite Solutions or No Solutions Related Study Materials.
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Oct 08, · mi-centre.com How to interpret a System of Equations that has "No Solution" or "Infinite Solutions".Download